(C) The work done by a gas at constant pressure is given by the formula:$W = P \Delta V$Given that the pressure $P$ is constant and the volume doubles

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(C) The work done by a gas at constant pressure is given by the formula:$W = P \Delta V$Given that the pressure $P$ is constant and the volume doubles from an initial volume $V$ to $2V$,the change in volume is $\Delta V = 2V - V = V$.Substituting this into the work formula:$W = P(V) = PV$According to the ideal gas equation,$PV = nRT$. For $n = 1$ mole of gas at temperature $T$,we have:$PV = RT$Therefore,the work done by the gas is:$W = RT$

Class 11 Physics Thermodynamics Isobaric and Isochoric Processes

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One mole of an ideal gas is contained within a cylinder by a frictionless piston and is initially at temperature $T$. The pressure of the gas is kept constant while it is heated and its volume doubles. If $R$ is the molar gas constant,the work done by the gas in increasing its volume is

A
$RT \ln 2$
B
$1/2 \, RT$
C
$RT$
D
$3/2 \, RT$

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Isobaric and Isochoric Processes

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One mole of an ideal gas is contained within a cylinder by a frictionless piston and is initially at temperature $T$. The pressure of the gas is kept constant while it is heated and its volume doubles. If $R$ is the molar gas constant,the work done by the gas in increasing its volume is

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