(A) The reaction of the complex with $AgNO_3$ to yield $2$ moles of $AgCl_{(s)}$ indicates that there are $2$ chloride ions $(Cl^-)$ present outside t

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(A) The reaction of the complex with $AgNO_3$ to yield $2$ moles of $AgCl_{(s)}$ indicates that there are $2$ chloride ions $(Cl^-)$ present outside the coordination sphere (ionizable chloride ions).When $[Co(NH_3)_5Cl]Cl_2$ dissolves in water,it dissociates as follows:$[Co(NH_3)_5Cl]Cl_2 \rightarrow [Co(NH_3)_5Cl]^{2+} + 2Cl^-$This results in a total of $1 + 2 = 3$ moles of ions per mole of the complex,which matches the given information.Therefore,the correct structure is $[Co(NH_3)_5Cl]Cl_2$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

One mole of the complex compound $Co(NH_3)_5Cl_3$ gives $3$ moles of ions on dissolution in water. One mole of the same complex reacts with two moles of $AgNO_3$ solution to yield two moles of $AgCl_{(s)}$. The structure of the complex is :-

AIEEE 2003 All AIEEE

A
$[Co(NH_3)_5Cl]Cl_2$
B
$[Co(NH_3)_3Cl_3] \cdot 2NH_3$
C
$[Co(NH_3)_4Cl_2]Cl \cdot NH_3$
D
$[Co(NH_3)_4Cl]Cl_2 \cdot NH_3$

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Determine the correct configuration of the following molecule:

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$A$ mass $m$ hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass $m$ and radius $R$. Assuming the pulley to be a perfect uniform circular disc,the acceleration of the mass $m$,if the string does not slip on the pulley,is:

AIEEE 2011

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Match the following and find the correct pairs.
List $I$ List $II$
$(A)$ Fleming's left hand rule $(i)$ Direction of induced current
$(B)$ Right hand thumb rule (ii) Magnitude and direction of magnetic induction
$(C)$ Biot-Savart law (iii) Direction of force due to magnetic induction
$(D)$ Fleming's right hand rule (iv) Direction of magnetic lines due to current

List $I$	List $II$
$(A)$ Fleming's left hand rule	$(i)$ Direction of induced current
$(B)$ Right hand thumb rule	(ii) Magnitude and direction of magnetic induction
$(C)$ Biot-Savart law	(iii) Direction of force due to magnetic induction
$(D)$ Fleming's right hand rule	(iv) Direction of magnetic lines due to current

TS EAMCET 2011

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Two cells $A$ and $B$ are connected in the secondary circuit of a potentiometer one at a time,and the balancing lengths are $400 \ cm$ and $440 \ cm$ respectively. The emf of cell $A$ is $1.08 \ V$. The emf of the second cell $B$ in volts is:

TS EAMCET 2004

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The position vectors of points $A, B, C$ and $D$ are $\vec A = 3\hat i + 4\hat j + 5\hat k, \vec B = 4\hat i + 5\hat j + 6\hat k, \vec C = 7\hat i + 9\hat j + 3\hat k$ and $\vec D = 4\hat i + 6\hat j$. Then the displacement vectors $\overrightarrow{AB}$ and $\overrightarrow{CD}$ are:

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One mole of the complex compound $Co(NH_3)_5Cl_3$ gives $3$ moles of ions on dissolution in water. One mole of the same complex reacts with two moles of $AgNO_3$ solution to yield two moles of $AgCl_{(s)}$. The structure of the complex is :-

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Determine the correct configuration of the following molecule:

$A$ mass $m$ hangs with the help of a string wrapped around a pulley on a frictionless bearing. The pulley has mass $m$ and radius $R$. Assuming the pulley to be a perfect uniform circular disc,the acceleration of the mass $m$,if the string does not slip on the pulley,is:

Two cells $A$ and $B$ are connected in the secondary circuit of a potentiometer one at a time,and the balancing lengths are $400 \ cm$ and $440 \ cm$ respectively. The emf of cell $A$ is $1.08 \ V$. The emf of the second cell $B$ in volts is:

The position vectors of points $A, B, C$ and $D$ are $\vec A = 3\hat i + 4\hat j + 5\hat k, \vec B = 4\hat i + 5\hat j + 6\hat k, \vec C = 7\hat i + 9\hat j + 3\hat k$ and $\vec D = 4\hat i + 6\hat j$. Then the displacement vectors $\overrightarrow{AB}$ and $\overrightarrow{CD}$ are:

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