One of the cube roots of unity is
- A$\frac{-1 + i\sqrt{3}}{2}$
- B$\frac{1 + i\sqrt{3}}{2}$
- C$\frac{1 - i\sqrt{3}}{2}$
- D$\frac{\sqrt{3} - i}{2}$
Explore More
Similar Questions
The value of $\sum_{k = 1}^{10} \left( \sin \frac{2k\pi}{11} + i\cos \frac{2k\pi}{11} \right)$ is
DifficultAIEEE 2006
View SolutionIf $\alpha$ is a non-real root of the equation $x^6-1=0$,then $\frac{\alpha^2+\alpha^3+\alpha^4+\alpha^5}{\alpha+1} = $
DifficultAP EAMCET 2017
View SolutionOne of the $15^{\text{th}}$ roots of $-1$ is
$\sum_{n=1}^{20} \left[ \sin \left( \frac{2n\pi}{21} \right) - i \cos \left( \frac{2n\pi}{21} \right) \right] = $
DifficultAP EAMCET 2017
View SolutionIf $1, \omega, \omega^2$ are the cube roots of unity,then the value of $(x+y)^2+(x \omega+y \omega^2)^2+(x \omega^2+y \omega)^2$ is
DifficultAP EAMCET 2022
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo