One of the factors of p(x) = x^{3} - 3x^{2} + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To find the factors of the polynomial $p(x) = x^{3} - 3x^{2} + 9x - 27$,we can use the method of grouping.Step $1$: Group the terms of the polynom

Vedclass · Accepted Answer

$x - 3$

Vedclass · Answer

(D) To find the factors of the polynomial $p(x) = x^{3} - 3x^{2} + 9x - 27$,we can use the method of grouping.Step $1$: Group the terms of the polynomial: $p(x) = (x^{3} - 3x^{2}) + (9x - 27)$.Step $2$: Factor out the common terms from each group: $p(x) = x^{2}(x - 3) + 9(x - 3)$.Step $3$: Factor out the common binomial $(x - 3)$: $p(x) = (x - 3)(x^{2} + 9)$.Thus,the factors are $(x - 3)$ and $(x^{2} + 9)$.Comparing this with the given options,$(x - 3)$ is one of the factors.

One of the factors of $p(x) = x^{3} - 3x^{2} + 9x - 27$ is.........

Similar Questions

The zeroes of the quadratic polynomial $x^{2}+99x+127$ are

Find the zeros of the cubic polynomial $p(x)=4 x^{3}+10 x^{2}+6 x$ and also verify the relationship between the zeros and the coefficients.

The number of real zeros of $y=p(x)$ is ......... in the given figure.

Find the zeros of the following quadratic polynomial: $p(x) = x^{2} + x - 12$.

The product of two polynomials is $x^{2}-x-72$ and if one of the polynomials is $(x+8)$,then the other polynomial is $\ldots \ldots \ldots \ldots . .$

Vedclass Test Series

Exam Paper Generator

Online Exam Module