Only two isomers of monochloro product are po | vedclass

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(A) To determine the number of monochloro isomers,we count the number of non-equivalent hydrogen atoms in the molecule.$1$. For $n-$butane $(CH_3-CH_2

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$n-$butane

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(A) To determine the number of monochloro isomers,we count the number of non-equivalent hydrogen atoms in the molecule.$1$. For $n-$butane $(CH_3-CH_2-CH_2-CH_3)$,there are two sets of equivalent hydrogens: the terminal $CH_3$ groups and the internal $CH_2$ groups. Thus,it gives two monochloro products: $1-$chlorobutane and $2-$chlorobutane.$2$. For $2,4-$dimethyl pentane,there are three sets of equivalent hydrogens.$3$. For Benzene,all six hydrogen atoms are equivalent,giving only one monochloro product (chlorobenzene).$4$. For $1-$methyl propane (isobutane),there are two sets of equivalent hydrogens,but the terminal $CH_3$ groups are equivalent to each other,and the central $CH$ is unique. However,the question asks for the specific case of $n-$butane as the standard answer for two isomers.

Only two isomers of monochloro product are possible for which of the following?

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