Which of the following coordination compounds | vedclass

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(C) To exhibit both optical and geometrical isomerism,a complex must have geometrical isomers,and at least one of those isomers must be chiral (non-su

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Only $a, b$

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(C) To exhibit both optical and geometrical isomerism,a complex must have geometrical isomers,and at least one of those isomers must be chiral (non-superimposable on its mirror image).$a$. $[Co(en)_2Cl_2]Br$: The cis-isomer is optically active (chiral),and it also exhibits geometrical isomerism (cis and trans forms). Thus,it satisfies the condition.$b$. $[Pt(NH_3)_2Cl_2Br_2]$: This is an octahedral complex of type $[M(A)_2(B)_2(C)_2]$. It exhibits multiple geometrical isomers,and specific configurations (like the facial isomer) can be optically active. Thus,it satisfies the condition.$c$. $[Co(en)_3]Cl_3$: This complex exhibits optical isomerism due to the presence of three bidentate ligands,but it does not exhibit geometrical isomerism.$d$. $[Pt(NH_3)_4Cl_2]$: This is an octahedral complex of type $[M(A)_4(B)_2]$. It exhibits geometrical isomerism (cis and trans),but both isomers possess planes of symmetry,making them optically inactive.$e$. $[Pt(NH_3)_2Cl_2]$: This is a square planar complex. It exhibits geometrical isomerism (cis and trans),but square planar complexes are inherently achiral due to the presence of a molecular plane of symmetry.Therefore,only $a$ and $b$ exhibit both types of isomerism.

Which of the following coordination compounds exhibit both optical and geometrical isomerism?
$a$. $[Co(en)_2Cl_2]Br$
$b$. $[Pt(NH_3)_2Cl_2Br_2]$
$c$. $[Co(en)_3]Cl_3$
$d$. $[Pt(NH_3)_4Cl_2]$
$e$. $[Pt(NH_3)_2Cl_2]$

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$(iv) \ [CoBrCl(en)_2]$

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The complexes given below show:

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Which of the following coordination compounds exhibit both optical and geometrical isomerism?$a$. $[Co(en)_2Cl_2]Br$$b$. $[Pt(NH_3)_2Cl_2Br_2]$$c$. $[Co(en)_3]Cl_3$$d$. $[Pt(NH_3)_4Cl_2]$$e$. $[Pt(NH_3)_2Cl_2]$