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(C) The magnetic dipole moment $M$ is defined by the relation $	au = M 	imes B$,where $	au$ is torque and $B$ is magnetic field.From this,$M = 	au

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$J / T$

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(C) The magnetic dipole moment $M$ is defined by the relation $	au = M 	imes B$,where $	au$ is torque and $B$ is magnetic field.From this,$M = 	au / B$.The unit of torque $	au$ is $N m$ (Newton-meter) and the unit of magnetic field $B$ is $T$ (Tesla).Therefore,the unit of $M$ is $N m / T$.Since $1 \ T = 1 \ Wb / m^2$,we can write $M = (N m) / (Wb / m^2) = N m^3 / Wb$.Also,$M = I A$,where $I$ is current $(A)$ and $A$ is area $(m^2)$,so the unit is $A m^2$.Since $1 \ J = 1 \ N m$,the unit $N m / T$ is equivalent to $J / T$.Comparing these with the options,$J-T$ (Option $C$) is dimensionally incorrect as it represents energy multiplied by magnetic field,not magnetic dipole moment.

Out of the following units,the $WRONG$ unit of magnetic dipole moment is

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