(B) To find the oxidation number of carbon $(x)$ in $CH_3Cl$:Assign oxidation states to other atoms: Hydrogen $(H)$ is $+1$ and Chlorine $(Cl)$ is $-1

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(B) To find the oxidation number of carbon $(x)$ in $CH_3Cl$:Assign oxidation states to other atoms: Hydrogen $(H)$ is $+1$ and Chlorine $(Cl)$ is $-1$.The sum of oxidation numbers in a neutral molecule is $0$.$x + 3(+1) + (-1) = 0$$x + 3 - 1 = 0$$x + 2 = 0$$x = -2$Therefore,the oxidation number of carbon is $-2$.