Ozone is found in

If a source of electromagnetic radiation having power $15 \text{ kW}$ produces $10^{16}$ photons per second,the radiation belongs to which part of the spectrum? (Take Planck constant $h = 6 \times 10^{-34} \text{ Js}$)

The energy of a gamma $(\gamma)$ ray photon is $E_{\gamma}$, and that of an $X$-ray photon is $E_{X}$. If the visible light photon has an energy of $E_{v}$, then we can say that:

$A$ charged particle oscillates about its mean equilibrium position with a frequency of $10^9 \ Hz$. The electromagnetic waves produced:

$A$ monochromatic source of light operating at $15 \text{ kW}$ emits $2.5 \times 10^{22} \text{ photons/s}$. The region of an electromagnetic spectrum to which the emitted electromagnetic radiation belongs to . . . . . . . (Take $h = 6.6 \times 10^{-34} \text{ J}\cdot\text{s}$ and $c = 3 \times 10^8 \text{ m/s}$).

The wavelengths of short radio waves,$X$-rays,and ultraviolet waves are $\lambda_{1}$,$\lambda_{2}$,and $\lambda_{3}$ respectively. Arrange them in decreasing order.