Pair of species among the following having sa | vedclass

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(C) To determine the bond order and magnetic nature, we use the Molecular Orbital Theory $(MOT)$ configuration:SpeciesBond Order and Magnetic Nature$O

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$O_{2}^{+}, N_{2}^{-}$

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(C) To determine the bond order and magnetic nature, we use the Molecular Orbital Theory $(MOT)$ configuration:SpeciesBond Order and Magnetic Nature$O_{2}^{+}$ ($15$ electrons)$2.5$, Paramagnetic$O_{2}^{-}$ ($17$ electrons)$1.5$, Paramagnetic$N_{2}^{+}$ ($13$ electrons)$2.5$, Paramagnetic$N_{2}^{-}$ ($15$ electrons)$2.5$, Paramagnetic$N_{2}^{2-}$ ($16$ electrons)$2.0$, Paramagnetic$N_{2}$ ($14$ electrons)$3.0$, DiamagneticComparing the options:$O_{2}^{+}$ has a bond order of $2.5$ and is paramagnetic.$N_{2}^{-}$ has a bond order of $2.5$ and is paramagnetic.Therefore, the pair $(O_{2}^{+}, N_{2}^{-})$ has the same bond order and magnetic character.

Pair of species among the following having same bond order as well as paramagnetic character will be -

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