The period of cot 3x - cos (4x + 3) is | vedclass

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(C) The period of $\cot 3x$ is $T_1 = \frac{\pi }{3}$.The period of $\cos (4x + 3)$ is $T_2 = \frac{2\pi }{4} = \frac{\pi }{2}$.The period of the func

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$\pi $

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(C) The period of $\cot 3x$ is $T_1 = \frac{\pi }{3}$.The period of $\cos (4x + 3)$ is $T_2 = \frac{2\pi }{4} = \frac{\pi }{2}$.The period of the function $f(x) = \cot 3x - \cos (4x + 3)$ is the $L.C.M.$ of $T_1$ and $T_2$.$L.C.M. \left( \frac{\pi }{3}, \frac{\pi }{2} \right) = \frac{L.C.M. (\pi, \pi)}{H.C.F. (3, 2)} = \frac{\pi }{1} = \pi$.Thus,the period is $\pi$.

The period of $\cot 3x - \cos (4x + 3)$ is

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