(A) The detector receives both direct and reflected waves,forming a standing wave pattern.The distance between two consecutive maxima in a standing wa

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(A) The detector receives both direct and reflected waves,forming a standing wave pattern.The distance between two consecutive maxima in a standing wave is $\lambda / 2$.For $14$ successive maxima,there are $13$ intervals of $\lambda / 2$.Given that the distance traveled is $0.13\, m$,we have:$13 \times \frac{\lambda}{2} = 0.13\, m$$\frac{\lambda}{2} = 0.01\, m$$\lambda = 0.02\, m$Using the relation $c = f \lambda$,where $c = 3 \times 10^8\, m/s$:$f = \frac{c}{\lambda} = \frac{3 \times 10^8}{0.02} = 1.5 \times 10^{10}\, Hz$.

Class 11 Physics Waves and Sound Stationary Waves (Standing wave)

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Plane microwaves from a transmitter are directed normally towards a plane reflector. $A$ detector moves along the normal to the reflector. Between positions of $14$ successive maxima,the detector travels a distance of $0.13\, m$. If the velocity of light is $3 \times 10^8\, m/s$,find the frequency of the transmitter.

A
$1.5 \times 10^{10}\, Hz$
B
$10^{10}\, Hz$
C
$3 \times 10^{10}\, Hz$
D
$6 \times 10^{10}\, Hz$

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Stationary Waves (Standing wave)

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The equation of a stationary wave along a stretched string is given by $y = 5 \sin \left( \frac{\pi x}{3} \right) \cos (40 \pi t)$. Here $x$ and $y$ are in $cm$ and $t$ is in seconds. The separation between two adjacent nodes is: (in $cm$)

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