The plate voltage of a triode is increased from $200 \, V$ to $225 \, V$. To maintain the plate current,a change in grid voltage from $5 \, V$ to $5.75 \, V$ is required. The amplification factor is:

The correct relation for a triode is:

For a triode,at ${V_g} = -1 \text{ V}$,the following observations were taken: ${V_p} = 75 \text{ V}, {I_p} = 2 \text{ mA}$ and ${V_p} = 100 \text{ V}, {I_p} = 4 \text{ mA}$. The value of plate resistance will be ...... $k\Omega$.

In a triode,${g_m} = 2 \times 10^{-3} \, \Omega^{-1}$,$\mu = 42$,and the resistance load $R_L = 50 \, \text{k}\Omega$. The voltage amplification obtained from this triode will be:

The slope of the plate characteristic of a vacuum diode is $2 \times 10^{-2} \, mA/V$. The plate resistance of the diode will be:

The amplification factor of a triode is $18$ and its plate resistance is $8 \times 10^{3} \ \Omega$. $A$ load resistance of $10^{4} \ \Omega$ is connected in the plate circuit. The voltage gain will be