Precipitate of group IV cations takes place w | vedclass

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(A) Group $IV$ cations $(Zn^{2+}, Mn^{2+}, Ni^{2+}, Co^{2+})$ are precipitated as their sulfides in the presence of $NH_4OH$ and $H_2S$. In this mediu

Vedclass · Accepted Answer

Highly ionised

Vedclass · Answer

(A) Group $IV$ cations $(Zn^{2+}, Mn^{2+}, Ni^{2+}, Co^{2+})$ are precipitated as their sulfides in the presence of $NH_4OH$ and $H_2S$. In this medium,the concentration of $S^{2-}$ ions is high due to the common ion effect and the basic medium,which exceeds the solubility product $(K_{sp})$ of group $IV$ sulfides. Therefore,$H_2S$ must be highly ionised to provide a sufficient concentration of sulfide ions for precipitation.

Column-$I$	Column-$II$
$(i)$ Blood like red colour	$(a)$ $Fe_4[Fe(CN)_6]_3$
$(ii)$ Sodium nitroprusside	$(b)$ $(NH_4)_2MoO_4$
$(iii)$ Ammonium molybdate	$(c)$ $[Fe(SCN)]^{2+}$
$(iv)$ Ferri-ferro cyanide	$(d)$ $Na_2[Fe(CN)_5NO]$

Precipitate of group $IV$ cations takes place when $H_2S$ is

Similar Questions

Which of the following compounds changes the color of an aqueous $FeCl_3$ solution?

Salt $X$ is:
$X \text{ (Colourless salt)}$ $\xrightarrow[\Delta]{NaOH} Y$ $\xrightarrow{HCl} \text{White fumes}$
$X \text{ (Colourless salt)}$ $\xrightarrow{CaCl_2} Z \text{ (White ppts.)}$ $\xrightarrow{KMnO_4} \text{Colourless solution}$

The compound that is white in color is

Choose an incorrect match of the colour of compounds.

Match column-$I$ and column-$II$ with correct relation:

Column-$I$ Column-$II$

$(i)$ Blood like red colour $(a)$ $Fe_4[Fe(CN)_6]_3$

$(ii)$ Sodium nitroprusside $(b)$ $(NH_4)_2MoO_4$

$(iii)$ Ammonium molybdate $(c)$ $[Fe(SCN)]^{2+}$

$(iv)$ Ferri-ferro cyanide $(d)$ $Na_2[Fe(CN)_5NO]$

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