Predict the correct reactivity order of the f | vedclass

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(A) The rate of $S_N1$ reaction is directly proportional to the stability of the carbocation intermediate formed after the departure of the leaving gr

Vedclass · Accepted Answer

$C_6H_5CH_2Br < C_6H_5CH(CH_3)Br < (C_6H_5)_2CHBr < (C_6H_5)_2C(CH_3)Br$

Vedclass · Answer

(A) The rate of $S_N1$ reaction is directly proportional to the stability of the carbocation intermediate formed after the departure of the leaving group $(Br^-)$.$1$. $C_6H_5CH_2^+$: Primary benzylic carbocation (stabilized by one phenyl ring).$2$. $C_6H_5CH(CH_3)^+$: Secondary benzylic carbocation (stabilized by one phenyl ring and one methyl group).$3$. $(C_6H_5)_2CH^+$: Secondary benzylic carbocation (stabilized by two phenyl rings).$4$. $(C_6H_5)_2C(CH_3)^+$: Tertiary benzylic carbocation (stabilized by two phenyl rings and one methyl group).Comparing stability: $C_6H_5CH_2^+ Thus,the reactivity order is $C_6H_5CH_2Br < C_6H_5CH(CH_3)Br < (C_6H_5)_2CHBr < (C_6H_5)_2C(CH_3)Br$.

Predict the correct reactivity order of the following compounds towards $S_N1$ reaction:

Similar Questions

Arrange the leaving group ability of the following groups in decreasing order:
$(I)$ $CH_3-C_6H_4-SO_3^-$,$(II)$ $C_6H_5-SO_3^-$,$(III)$ $N_3^-$,$(IV)$ $Br^-$

The product $(C)$ in the following reaction sequence is:

The major product obtained in the reaction of $1$-phenyl-$2$-bromobutane with $NaOMe$ is:

The reaction of $4-methylcyclohexyl$ halide with $OH^-$ via the $S_N2$ mechanism produces $A$. Identify $A$.

Which among the following statements is $NOT$ correct about $SN^2$ reaction mechanism?

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