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(D) The reaction sequence is as follows:$1$. Phenol reacts with $CO_2$ in the presence of $NaOH$ (Kolbe-Schmitt reaction) to form sodium salicylate,wh

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(D) The reaction sequence is as follows:$1$. Phenol reacts with $CO_2$ in the presence of $NaOH$ (Kolbe-Schmitt reaction) to form sodium salicylate,which upon acidification gives salicylic acid $(A)$,which is $2$-hydroxybenzoic acid.$2$. Salicylic acid $(A)$ reacts with acetic anhydride $(Ac_2O)$ in the presence of an acid catalyst to undergo acetylation of the phenolic $-OH$ group,forming $2$-acetoxybenzoic acid $(B)$,commonly known as aspirin.$3$. The structure of $(B)$ is a benzene ring with a $-COOH$ group at position $1$ and a $-OCOCH_3$ group at position $2$.

The product $(B)$ will be:

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