The product A of the following reaction is: R | vedclass

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(C) The reductive ozonolysis of an alkene with the structure $R_2C=CHR'$ involves the cleavage of the carbon-carbon double bond. The reaction proceeds

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$R_2C=O + R'-CHO$

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(C) The reductive ozonolysis of an alkene with the structure $R_2C=CHR'$ involves the cleavage of the carbon-carbon double bond. The reaction proceeds via the formation of an ozonide intermediate,which is then reduced by $Zn/H_2O$ or dimethyl sulfide to yield carbonyl compounds. The cleavage of $R_2C=CHR'$ results in the formation of a ketone $(R_2C=O)$ and an aldehyde $(R'-CHO)$. Therefore,the product $A$ is a mixture of $R_2C=O$ and $R'-CHO$.

The product $A$ of the following reaction is:
$R_2C=CHR' \xrightarrow[Zn/H_2O]{O_3} A$

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The product $A$ of the following reaction is: $R_2C=CHR' \xrightarrow[Zn/H_2O]{O_3} A$