The product (C) of the reaction is: | vedclass

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(B) $1$. Cyclopentanone reacts with hydroxylamine $(NH_2OH)$ to form cyclopentanone oxime $(A)$.$2$. In the presence of an acid $(H^+)$,the oxime unde

Vedclass · Accepted Answer

Piperidine

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(B) $1$. Cyclopentanone reacts with hydroxylamine $(NH_2OH)$ to form cyclopentanone oxime $(A)$.$2$. In the presence of an acid $(H^+)$,the oxime undergoes Beckmann rearrangement to form a cyclic amide,$\epsilon$-caprolactam $(B)$.$3$. Reduction of the amide $(B)$ with lithium aluminium hydride $(LAH)$ yields the corresponding cyclic amine,piperidine $(C)$.

The product $(C)$ of the reaction is:

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