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Question

(C) $1$. The starting material is $1$-methylcyclopentanol. Upon treatment with $H^+/\Delta$,it undergoes dehydration to form $1$-methylcyclopent$-1-$e

Vedclass · Accepted Answer

$3-$methylcyclopent$-2-$en$-1-$one

Vedclass · Answer

(C) $1$. The starting material is $1$-methylcyclopentanol. Upon treatment with $H^+/\Delta$,it undergoes dehydration to form $1$-methylcyclopent$-1-$ene $(A)$.$2$. Ozonolysis of $(A)$ $(O_3/Zn)$ results in the cleavage of the double bond to form a diketone,$6$-oxoheptanal $(B)$,which is $CH_3COCH_2CH_2CH_2CHO$.$3$. Compound $(B)$ contains both a ketone and an aldehyde group. In the presence of $HO^-/\Delta$,it undergoes intramolecular aldol condensation. The enolate forms at the $\alpha$-carbon of the ketone,which then attacks the aldehyde carbonyl group to form a five-membered ring,resulting in $3$-methylcyclopent$-2-$en$-1-$one $(C)$.

Product $(C)$ is

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