Identify the products A,B,and C in the follow | vedclass

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(B) $1$. The reaction of benzamide $(C_6H_5CONH_2)$ with $P_2O_5$ followed by heating causes dehydration to form benzonitrile $(A = C_6H_5CN)$.$2$. Th

Vedclass · Accepted Answer

$A$ = $C_6H_5CN$,$B$ = $C_6H_5CHO$,$C$ = $C_6H_5CH=CHCOOH$

Vedclass · Answer

(B) $1$. The reaction of benzamide $(C_6H_5CONH_2)$ with $P_2O_5$ followed by heating causes dehydration to form benzonitrile $(A = C_6H_5CN)$.$2$. The reduction of benzonitrile $(C_6H_5CN)$ with $DIBAL-H$ followed by hydrolysis yields benzaldehyde $(B = C_6H_5CHO)$.$3$. The reaction of benzaldehyde $(C_6H_5CHO)$ with acetic anhydride $((CH_3CO)_2O)$ in the presence of sodium acetate $(CH_3COONa)$ is the Perkin condensation,which yields cinnamic acid $(C = C_6H_5CH=CHCOOH)$ after acidic hydrolysis.

List-$I$	List-$II$
$A$. Tollen's reagent	$I$. Para-rosaniline + $SO_2$
$B$. Schiff's reagent	$II$. Rochelle salt + $aq. NaOH$
$C$. Rosenmund reduction	$III$. Ammoniacal silver nitrate
$D$. Fehling solution $B$	$IV$. $Pd + BaSO_4$

Identify the products $A$,$B$,and $C$ in the following reaction sequence:
$C_6H_5CONH_2$ $\xrightarrow{P_2O_5, \Delta} A$ $\xrightarrow[(ii) H_2O]{(i) DIBAL-H} B$
$A \xrightarrow[(ii) H_3O^+, \Delta]{(i) (CH_3CO)_2O/CH_3COONa} C$

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Identify the products $A$,$B$,and $C$ in the following reaction sequence:$C_6H_5CONH_2$ $\xrightarrow{P_2O_5, \Delta} A$ $\xrightarrow[(ii) H_2O]{(i) DIBAL-H} B$$A \xrightarrow[(ii) H_3O^+, \Delta]{(i) (CH_3CO)_2O/CH_3COONa} C$