The product (B) in the given reaction is: | vedclass

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(C) $1$. The reaction of aniline with $Br_2/H_2O$ leads to electrophilic aromatic substitution,resulting in the formation of $2,4,6$-tribromoaniline a

Vedclass · Accepted Answer

$1,3,5-$tribromobenzene

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(C) $1$. The reaction of aniline with $Br_2/H_2O$ leads to electrophilic aromatic substitution,resulting in the formation of $2,4,6$-tribromoaniline as product $(A)$.$2$. The treatment of $2,4,6$-tribromoaniline with $(i) NaNO_2/HCl$ at low temperature $(0-5 \ ^\circ C)$ forms the corresponding diazonium salt,$2,4,6$-tribromobenzenediazonium chloride.$3$. Subsequent treatment with $H_3PO_2$ (hypophosphorous acid) and water reduces the diazonium group to a hydrogen atom,resulting in the formation of $1,3,5$-tribromobenzene as product $(B)$.

The product $(B)$ in the given reaction is:

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