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(B) The reaction proceeds through the following steps:$1$. Protonation of the hydroxyl group: The $-OH$ group is protonated by $H^{\oplus}$ to form a

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o-Xylene

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(B) The reaction proceeds through the following steps:$1$. Protonation of the hydroxyl group: The $-OH$ group is protonated by $H^{\oplus}$ to form a good leaving group $-OH_2^{\oplus}$.$2$. Formation of carbocation: Loss of water molecule generates a carbocation.$3$. Rearrangement: $A$ $1,2-CH_3$ shift occurs to stabilize the carbocation and form a more stable intermediate.$4$. Deprotonation: Loss of a proton $(-H^{\oplus})$ leads to the formation of the aromatic product,$o$-xylene ($1,2$-dimethylbenzene).

Product $(A)$ is

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