The product which is not expected to be formed in the following reaction is:
$C_6H_5CHO + CH_3CH_2CHO \xrightarrow{OH^-(aq.), \Delta} \text{Product}$

  • A
    $C_6H_5CH=CH-CH_2-CHO$
  • B
    $CH_3-CH_2-CH=C(CH_3)-CHO$
  • C
    $C_6H_5CH=C(CH_3)-CHO$
  • D
    All

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An optically active alkyl halide $C_4H_9Br$ $[A]$ reacts with hot $KOH$ dissolved in ethanol and forms alkene $[B]$ as the major product,which reacts with bromine to give dibromide $[C].$ The compound $[C]$ is converted into a gas $[D]$ upon reacting with alcoholic $NaNH_2.$ During hydration,$18 \ g$ of water is added to $1 \ mole$ of gas $[D]$ on warming with mercuric sulphate and dilute acid at $333 \ K$ to form compound $[E].$ The $IUPAC$ name of compound $[E]$ is $:$

Compound $X$ undergoes the following reaction sequence. What is the structure of compound $X$?

Consider the reactions and identify $A, X, Y$ and $Z$:
$X (C_2H_6O)$ $\xrightarrow{Cu, 573 \ K} A$ $\xrightarrow{[Ag(NH_3)_2]^+, ^-OH, \Delta} \text{Silver mirror}$
$A \xrightarrow{^-OH, \Delta} Y$
$A \xrightarrow{NH_2NHCONH_2} Z$

Which of the following will not give the iodoform test?

The product $(A)$ of the following reaction is:

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