Propene,when heated with chlorine at approximately $500^\circ C$,forms:

$A$ hydrocarbon containing $2$ carbon atoms gives Sabatier and Senderen's reaction but does not give a precipitate with ammoniacal silver nitrate solution. The hydrocarbon is:

The reaction of $2-$methylbuta$-1,3-$diene with $O_3$ followed by $Zn-H_2O$ gives:

Which of the following is the most stable alkene?

In the given reaction,only one alkene undergoes preferential oxidation by electrophilic ozone. Identify the product $(P)$ of the given reaction.

$(CH_3)_2C=C(CH_3)_2 \xrightarrow{\text{Catalyst}, H_2} \text{Number of optical isomers in the product?}$