Range of the function f(x) = 9 - 7sin x is | vedclass

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(B) We know that the range of the sine function $\sin x$ is $[-1, 1]$.This means $-1 \le \sin x \le 1$.Multiplying by $-7$,we get $7 \ge -7 \sin x \ge

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$[2, 16]$

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(B) We know that the range of the sine function $\sin x$ is $[-1, 1]$.This means $-1 \le \sin x \le 1$.Multiplying by $-7$,we get $7 \ge -7 \sin x \ge -7$,which can be written as $-7 \le -7 \sin x \le 7$.Adding $9$ to all parts of the inequality,we get $9 - 7 \le 9 - 7 \sin x \le 9 + 7$.Thus,$2 \le 9 - 7 \sin x \le 16$.Therefore,the range of the function $f(x) = 9 - 7 \sin x$ is $[2, 16]$.

Range of the function $f(x) = 9 - 7\sin x$ is

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