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(C) The intensity $I$ of a wave is directly proportional to the square of its amplitude $a$,i.e.,$I \propto a^2$.Given the ratio of amplitudes is $\fr

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$9/16$

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(C) The intensity $I$ of a wave is directly proportional to the square of its amplitude $a$,i.e.,$I \propto a^2$.Given the ratio of amplitudes is $\frac{a_1}{a_2} = \frac{3}{4}$.The ratio of their intensities is given by $\frac{I_1}{I_2} = \left( \frac{a_1}{a_2} \right)^2$.Substituting the values: $\frac{I_1}{I_2} = \left( \frac{3}{4} \right)^2 = \frac{9}{16}$.Therefore,the ratio of their intensities is $9:16$.

The ratio of the amplitudes of two interfering waves is $3 : 4$. What is the ratio of their intensities?

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