The ratio of the energy of a photon with wave | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,the energy $E$ is inversely proportional t

Vedclass · Accepted Answer

$2 : 1$

Vedclass · Answer

(B) The energy of a photon is given by the formula $E = \frac{hc}{\lambda}$.Since $h$ and $c$ are constants,the energy $E$ is inversely proportional to the wavelength $\lambda$,i.e.,$E \propto \frac{1}{\lambda}$.Therefore,the ratio of energies is $\frac{E_1}{E_2} = \frac{\lambda_2}{\lambda_1}$.Given $\lambda_1 = 3000 \ \mathring{A}$ and $\lambda_2 = 6000 \ \mathring{A}$.Substituting the values,we get $\frac{E_1}{E_2} = \frac{6000}{3000} = \frac{2}{1}$.Thus,the ratio is $2 : 1$.

The ratio of the energy of a photon with wavelength $3000 \ \mathring{A}$ to that of a photon with wavelength $6000 \ \mathring{A}$ is:

Similar Questions

What is a black body?

$A$ photon-sensitive metal is not emitting photoelectrons when irradiated. It will do so when the threshold is crossed. To cross the threshold,we need to increase:

Which one of the following frequencies of radiation (in $Hz$) has a wavelength of $600 \ nm$?

Explain the reason for the formation of a spectrum.

Work functions of four metals $M_1, M_2, M_3$ and $M_4$ are $4.8, 4.3, 4.75$ and $3.75 \ eV$ respectively. The metals which do not show photoelectric effect when light of wavelength $310 \ nm$ falls on the metals are

Vedclass Test Series

Exam Paper Generator

Online Exam Module