Work functions of four metals M_1, M_2, M_3 a | vedclass

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(C) The energy of the incident photon is given by $E = \frac{hc}{\lambda}$.Given $\lambda = 310 \ nm = 310 	imes 10^{-9} \ m$.Using $h = 6.626 	imes

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$M_1, M_2, M_3$ only

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(C) The energy of the incident photon is given by $E = \frac{hc}{\lambda}$.Given $\lambda = 310 \ nm = 310 	imes 10^{-9} \ m$.Using $h = 6.626 	imes 10^{-34} \ J \cdot s$ and $c = 3 	imes 10^8 \ m/s$, $E = \frac{6.626 	imes 10^{-34} 	imes 3 	imes 10^8}{310 	imes 10^{-9}} \approx 6.41 	imes 10^{-19} \ J$.Converting to $eV$: $E = \frac{6.41 	imes 10^{-19}}{1.602 	imes 10^{-19}} \approx 4.0 \ eV$.Photoelectric effect occurs if the energy of the incident photon is greater than or equal to the work function $(\Phi)$ of the metal. If $E Here, $E = 4.0 \ eV$.Comparing with work functions:$M_1: 4.8 \ eV > 4.0 \ eV$ (No effect)$M_2: 4.3 \ eV > 4.0 \ eV$ (No effect)$M_3: 4.75 \ eV > 4.0 \ eV$ (No effect)$M_4: 3.75 \ eV Thus, $M_1, M_2$ and $M_3$ do not show the photoelectric effect.

Work functions of four metals $M_1, M_2, M_3$ and $M_4$ are $4.8, 4.3, 4.75$ and $3.75 \ eV$ respectively. The metals which do not show photoelectric effect when light of wavelength $310 \ nm$ falls on the metals are

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