Rationalise the denominator of frac{5}{sqrt{3 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) To rationalise the denominator,we multiply the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{3}+\sqrt{5})$.$\

Vedclass · Accepted Answer

$-\frac{5}{2}(\sqrt{3}+\sqrt{5})$

Vedclass · Answer

(B) To rationalise the denominator,we multiply the numerator and the denominator by the conjugate of the denominator,which is $(\sqrt{3}+\sqrt{5})$.$\frac{5}{\sqrt{3}-\sqrt{5}} = \frac{5}{\sqrt{3}-\sqrt{5}} 	imes \frac{\sqrt{3}+\sqrt{5}}{\sqrt{3}+\sqrt{5}}$Using the algebraic identity $(a-b)(a+b) = a^2 - b^2$ in the denominator:$= \frac{5(\sqrt{3}+\sqrt{5})}{(\sqrt{3})^2 - (\sqrt{5})^2}$$= \frac{5(\sqrt{3}+\sqrt{5})}{3 - 5}$$= \frac{5(\sqrt{3}+\sqrt{5})}{-2}$$= -\frac{5}{2}(\sqrt{3}+\sqrt{5})$

Rationalise the denominator of $\frac{5}{\sqrt{3}-\sqrt{5}}$.

Similar Questions

You know that $\frac{1}{7} = 0.\overline{142857}$. Can you predict what the decimal expansions of $\frac{2}{7}, \frac{3}{7}, \frac{4}{7}, \frac{5}{7}, \frac{6}{7}$ are,without actually doing the long division? If so,how?

Find three different irrational numbers between the rational numbers $\frac{5}{7}$ and $\frac{9}{11}$.

Rationalise the denominator of $\frac{1}{\sqrt{2}}$.

Classify the following numbers as rational or irrational:
$(i)$ $\sqrt{23}$
$(ii)$ $\sqrt{225}$
$(iii)$ $0.3796$
$(iv)$ $7.478478 \ldots$
$(v)$ $1.101001000100001 \ldots$

Rationalise the denominator of $\frac{1}{7+3 \sqrt{2}}$

Vedclass Test Series

Exam Paper Generator

Online Exam Module