Reaction of an inorganic sulphite $X$ with dilute $H_{2}SO_{4}$ generates compound $Y$. Reaction of $Y$ with $NaOH$ gives $X$. Further,the reaction of $X$ with $Y$ and water affords compound $Z$. $Y$ and $Z$,respectively,are:

  • A
    $S$ and $Na_{2}SO_{3}$
  • B
    $SO_{2}$ and $NaHSO_{3}$
  • C
    $SO_{3}$ and $NaHSO_{3}$
  • D
    $SO_{2}$ and $Na_{2}SO_{3}$

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