Relation R on set N is defined as follows:R = | vedclass

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(D) The relation is defined as $R = \{(a, b) : a = b - 2, b > 6\}$.We test each option:$A$: For $(2, 4)$,$b = 4$. Since $4 
gtr 6$,$(2, 4) 
otin R$.

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$(6, 8) \in R$

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(D) The relation is defined as $R = \{(a, b) : a = b - 2, b > 6\}$.We test each option:$A$: For $(2, 4)$,$b = 4$. Since $4 
gtr 6$,$(2, 4) 
otin R$.$B$: For $(8, 7)$,$a = 8$ and $b = 7$. Here $a = b - 2$ implies $8 = 7 - 2$,which is $8 = 5$ (False).$C$: For $(3, 8)$,$a = 3$ and $b = 8$. Here $a = b - 2$ implies $3 = 8 - 2$,which is $3 = 6$ (False).$D$: For $(6, 8)$,$a = 6$ and $b = 8$. Here $b > 6$ is $8 > 6$ (True),and $a = b - 2$ implies $6 = 8 - 2$,which is $6 = 6$ (True).Thus,$(6, 8) \in R$.

Relation $R$ on set $N$ is defined as follows:
$R = \{(a, b) : a = b - 2, b > 6\}$. Select the appropriate option.

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Relation $R$ on set $N$ is defined as follows:$R = \{(a, b) : a = b - 2, b > 6\}$. Select the appropriate option.