The solution set of $x \equiv 3 \pmod{7}$,where $x \in \mathbb{Z}$,is:

The figure shows a relationship between the sets $P$ and $Q$. Write this relation in set-builder form. What is its domain and range?

Given $A = \{1, 2, 3, 4, 5\}$ and $B = \{1, 4, 5\}$. If $R$ is a relation from $A$ to $B$ such that $(x, y) \in R$ with $x > y$,then the range of $R$ is:

Let $A = \{11, 12, 13\}$ and $B = \{8, 10, 12\}$. $A$ relation $R$ from $A$ to $B$ is defined by $y = x - 3$. Then,find $R^{-1}$.

Let $A = \{1, 2, 3, 4, 6\}$. Let $R$ be the relation on $A$ defined by $R = \{(a, b) : a, b \in A, b \text{ is exactly divisible by } a\}$. Write $R$ in roster form.

If $A = \{x, y, z\}$ and $B = \{1, 2\}$,then the total number of relations from set $A$ to set $B$ is: