Resistances are arranged in a cyclic order to form a balanced Wheatstone bridge as shown in the figure. The ratio of power consumed in the branches $(P + Q)$ and $(R + S)$ is

Kirchhoff's first law,$i.e.$,$\Sigma i = 0$ at a junction,is based on the law of conservation of:

As shown in the circuit diagram,find the value of $I = \text{ . . . . . . }$. (in $\text{ A}$)

Five resistors,each of resistance $R$,are arranged as shown in the figure. $A$ battery of voltage $V$ is connected between points $A$ and $B$. Find the current flowing through the branch $AFCEB$.

In the given circuit diagram,the currents $I_1 = -0.3\,A$,$I_4 = 0.8\,A$ and $I_5 = 0.4\,A$ are flowing as shown. The currents $I_2, I_3$ and $I_6$ respectively are

The Wheatstone bridge shown in the figure gets balanced when the carbon resistor used as $R_1$ has the colour code (Orange,Red,Brown). The resistors $R_2$ and $R_4$ are $80 \, \Omega$ and $40 \, \Omega$,respectively. Assuming that the colour code for the carbon resistors gives their accurate values,the colour code for the carbon resistor used as $R_3$ would be