Resolve into factors: 9(3 x+5 y)^{2}-12(3 x+5 | vedclass

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(B) The given expression is $9(3 x+5 y)^{2}-12(3 x+5 y)(2 x+3 y)+4(2 x+3 y)^{2}$.This expression is in the form of $a^{2}-2ab+b^{2}$,where $a = 3(3 x+

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$(5 x+9 y)^{2}$

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(B) The given expression is $9(3 x+5 y)^{2}-12(3 x+5 y)(2 x+3 y)+4(2 x+3 y)^{2}$.This expression is in the form of $a^{2}-2ab+b^{2}$,where $a = 3(3 x+5 y)$ and $b = 2(2 x+3 y)$.We can rewrite the expression as:$[3(3 x+5 y)]^{2}-2[3(3 x+5 y)][2(2 x+3 y)]+[2(2 x+3 y)]^{2}$.Using the identity $(a-b)^{2} = a^{2}-2ab+b^{2}$,we get:$[3(3 x+5 y)-2(2 x+3 y)]^{2}$.Now,simplify the expression inside the bracket:$= (9 x+15 y-4 x-6 y)^{2}$.$= (5 x+9 y)^{2}$.

Resolve into factors: $9(3 x+5 y)^{2}-12(3 x+5 y)(2 x+3 y)+4(2 x+3 y)^{2}$

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