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(B) For Rolle's theorem to be applicable to a function $f(x)$ on an interval $[a, b]$,the following conditions must be met:$1$. $f(x)$ must be continu

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$[-2, 2]$

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(B) For Rolle's theorem to be applicable to a function $f(x)$ on an interval $[a, b]$,the following conditions must be met:$1$. $f(x)$ must be continuous on $[a, b]$.$2$. $f(x)$ must be differentiable on $(a, b)$.$3$. $f(a) = f(b)$.Given $f(x) = x^2 - 4$,which is a polynomial function,it is continuous and differentiable everywhere.We check the condition $f(a) = f(b)$ for the given options:For option $(b)$,the interval is $[-2, 2]$.$f(-2) = (-2)^2 - 4 = 4 - 4 = 0$.$f(2) = (2)^2 - 4 = 4 - 4 = 0$.Since $f(-2) = f(2)$,Rolle's theorem is applicable on the interval $[-2, 2]$.

Rolle's theorem is applicable for the function $f(x) = x^2 - 4$ in which of the following intervals?

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