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(B) The bond angles for $NO_2^+$,$NO_2$,and $NO_2^-$ are $180^{\circ}$,$134^{\circ}$,and $115^{\circ}$ respectively.As we move from $NO_2^+$ to $NO_2^

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Decrease of $O-N-O$ bond angle

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(B) The bond angles for $NO_2^+$,$NO_2$,and $NO_2^-$ are $180^{\circ}$,$134^{\circ}$,and $115^{\circ}$ respectively.As we move from $NO_2^+$ to $NO_2^-$,the number of lone pairs on the central nitrogen atom increases,which causes greater repulsion and leads to a decrease in the $O-N-O$ bond angle.$NO_2^+$ is $sp$ hybridized (linear),$NO_2$ is $sp^2$ hybridized (bent),and $NO_2^-$ is $sp^2$ hybridized (bent).Therefore,the correct statement is the decrease of the $O-N-O$ bond angle.

Select the correct statement regarding the following change:
$NO_2^+ \to NO_2 \to NO_2^-$

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Select the correct statement regarding the following change:$NO_2^+ \to NO_2 \to NO_2^-$