Identify the correct statement regarding geom | vedclass

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(C) In $CH_4$,the central carbon atom is $sp^3$ hybridized and forms $4$ sigma bonds with hydrogen atoms. It has $0$ lone pairs and a tetrahedral geom

Vedclass · Accepted Answer

Both have same geometry with no lone pair of electrons each.

Vedclass · Answer

(C) In $CH_4$,the central carbon atom is $sp^3$ hybridized and forms $4$ sigma bonds with hydrogen atoms. It has $0$ lone pairs and a tetrahedral geometry.In $SiCl_4$,the central silicon atom is $sp^3$ hybridized and forms $4$ sigma bonds with chlorine atoms. It has $0$ lone pairs and a tetrahedral geometry.Therefore,both molecules have the same tetrahedral geometry and contain no lone pairs of electrons on the central atom.

Identify the correct statement regarding geometry and lone pair of electrons present in $CH_4$ and $SiCl_4$.

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