Select the correct statement for an ideal solution of a non-volatile solute in a liquid solvent.

  • A
    Heat of vaporisation for a pure solvent and for a solution are similar because similar intermolecular forces between solvent molecules must be overcome in both cases.
  • B
    Entropy change between solution and vapour is smaller than the entropy change between pure solvent and vapour.
  • C
    Boiling point of the solution is higher than that of the pure solvent.
  • D
    All are correct statements.

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Similar Questions

At $300 \ K$,an ideal solution is formed by mixing $460 \ g$ of toluene with $390 \ g$ of benzene. If the vapour pressure of pure toluene and pure benzene at $300 \ K$ are $32 \ mm$ and $40 \ mm$ respectively,the mole fraction of toluene in the vapour phase is:

Match the following.
List-$I$ List-$II$
$(A)$ Azeotrope $(I)$ $\Delta T_b = i K_b m$
$(B)$ Henry's law $(II)$ $p = K_H x$
$(C)$ Cryoscopic constant $(III)$ $\Delta T_f / m$
$(D)$ Van't Hoff factor $(IV)$ Deviation from Raoult's law
$(V)$ $\pi = CRT$

The correct answer is

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$6 \ g$ of a mixture of naphthalene $(C_{10}H_8)$ and anthracene $(C_{14}H_{10})$ is dissolved in $300 \ g$ of benzene. If the depression in freezing point is $0.70 \ K$,the composition of naphthalene and anthracene in the mixture respectively in $g$ are (molal depression constant of benzene is $5.1 \ K \ kg \ mol^{-1}$)

After adding a non-volatile solute, the freezing point of water decreases to $-0.186^{\circ} C$. Calculate $\Delta T_b$ if $K_f = 1.86 \text{ K kg mol}^{-1}$ and $K_b = 0.521 \text{ K kg mol}^{-1}$. (in $\text{ K}$)

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