Select the correct order of Delta_o (Crystal | vedclass

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(C) The magnitude of crystal field splitting energy $(\Delta_o)$ depends on several factors:$1$. Nature of the ligand: Strong field ligands (like $CN^

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$[M(H_2O)_6]^{3+} < [M(NO_2)_6]^{3-} < [M(CN)_6]^{3-}$

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(C) The magnitude of crystal field splitting energy $(\Delta_o)$ depends on several factors:$1$. Nature of the ligand: Strong field ligands (like $CN^-$) cause larger splitting than weak field ligands (like $H_2O$). The spectrochemical series order is $H_2O $2$. Oxidation state of the metal: Higher oxidation states lead to larger $\Delta_o$ values.$3$. Principal quantum number $(n)$: For the same group,$\Delta_o$ increases down the group $(3d Evaluating the options:- Option $A$ is incorrect because the order should be $3d - Option $B$ is incorrect because octahedral complexes generally have larger $\Delta_o$ than tetrahedral complexes.- Option $C$ is correct based on the spectrochemical series: $H_2O$ is a weaker ligand than $NO_2^-$,which is weaker than $CN^-$.- Option $D$ is correct because higher oxidation state of the metal ion $(M^{3+} > M^{2+})$ results in greater $\Delta_o$.

$I$. $H_2O$	$II$. $CO$
$III$. $NH_3$	$IV$. $I^{-}$
$V$. $F^{-}$

Select the correct order of $\Delta_o$ (Crystal Field Splitting Energy).

Similar Questions

Arrange the following ligands in the order of increasing field strength.
$I$. $H_2O$ $II$. $CO$
$III$. $NH_3$ $IV$. $I^{-}$
$V$. $F^{-}$

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