Select the correct statement.

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(D) Option $(A)$ is correct because the carbocation formed from $(CH_3)_2C=CH-CH_2-Cl$ is resonance-stabilized,making it much more reactive in solvoly

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All of these

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(D) Option $(A)$ is correct because the carbocation formed from $(CH_3)_2C=CH-CH_2-Cl$ is resonance-stabilized,making it much more reactive in solvolysis compared to a simple alkyl chloride.Option $(B)$ is correct because the reaction of $CH_3-CH=CH-CH_2-OH$ with $HBr$ involves the formation of an allylic carbocation intermediate,which can be attacked by $Br^-$ at two different positions,leading to a mixture of $1$-bromo-$2$-butene and $3$-bromo-$1$-butene.Option $(C)$ is correct because $3$-buten-$2$-ol in aqueous acid undergoes protonation and loss of water to form an allylic carbocation,which can be attacked by water at either the $C-1$ or $C-3$ position,leading to an equilibrium mixture of $3$-buten-$2$-ol and $2$-buten-$1$-ol.Since all statements are correct,the correct answer is $(D)$.

Group-$I$ (Compound)	Group-$II$ (Use)
$A$. Alcohol	$1$. Antiseptic
$B$. Phenol	$2$. Perfumes
$C$. Ether	$3$. Detergents
$D$. Amine	$4$. Dyes

Similar Questions

Identify product $B$ in the following reaction sequence:
$(CH_3)_2C=C(CH_3)_2$ $\xrightarrow{X_2, H_2O} A$ $\xrightarrow{OH^{-}} B$

Arrange the following compounds in the increasing order of their boiling points:
$CH_3CH_2CH_2CHO$,$CH_3CH_2CH_2CH_2OH$,$C_2H_5OC_2H_5$,$CH_3CH_2CH_2CH_3$

Match the compounds in Group-$I$ with their uses in Group-$II$. Find the correct match for Group-$I$ from Group-$II$.

Group-$I$ (Compound) Group-$II$ (Use)

$A$. Alcohol $1$. Antiseptic

$B$. Phenol $2$. Perfumes

$C$. Ether $3$. Detergents

$D$. Amine $4$. Dyes

Explain the following with an example.
$(i)$ Kolbe's reaction.
$(ii)$ Reimer-Tiemann reaction.
$(iii)$ Williamson ether synthesis.
$(iv)$ Unsymmetrical ether.

Identify the major product of the following reaction:

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