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(C) The given complex is $[Co(NH_3)_4Cl_2]Cl$.In aqueous solution,it ionizes as: $[Co(NH_3)_4Cl_2]Cl \rightarrow [Co(NH_3)_4Cl_2]^+ + Cl^-$.This produ

Vedclass · Accepted Answer

It gives one mole of $AgCl$ precipitate on reaction with excess of $AgNO_3$.

Vedclass · Answer

(C) The given complex is $[Co(NH_3)_4Cl_2]Cl$.In aqueous solution,it ionizes as: $[Co(NH_3)_4Cl_2]Cl \rightarrow [Co(NH_3)_4Cl_2]^+ + Cl^-$.This produces two ions in solution,so option $A$ is incorrect.The primary valency of a metal in a coordination compound corresponds to its oxidation state. Here,$x + 4(0) + 3(-1) = 0$,so $x = +3$. Thus,the primary valency is $3$,not $6$,making option $B$ incorrect.Since there is one $Cl^-$ ion outside the coordination sphere,it reacts with $AgNO_3$ to give one mole of $AgCl$ precipitate: $Cl^- + AgNO_3 \rightarrow AgCl(s) + NO_3^-$. Thus,option $C$ is correct.The primary valency is the oxidation state,which is $3$,not $1$,making option $D$ incorrect.

Select the correct statement about the given complex $[Co(NH_3)_4Cl_2]Cl$.

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