Select the incorrect statement using the phas | vedclass

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(C) $1$. In the given phase diagram,the line $OB$ represents the solid-liquid equilibrium (melting/freezing curve). At pressure $P_2$,the intersection

Vedclass · Accepted Answer

At $T_3$ temperature,the vapour pressure of the liquid is $P_1$.

Vedclass · Answer

(C) $1$. In the given phase diagram,the line $OB$ represents the solid-liquid equilibrium (melting/freezing curve). At pressure $P_2$,the intersection with the $OB$ line is at temperature $T_4$,which is the melting point. Thus,statement $A$ is correct.$2$. At pressure $P_2$,the region between the solid-liquid curve $(OB)$ and the liquid-vapour curve $(OA)$ represents the liquid phase. For $T_4 $3$. At temperature $T_3$,the pressure $P_1$ lies below the liquid-vapour curve $(OA)$,meaning the substance is in the vapour state,not the liquid state. The vapour pressure of the liquid at $T_3$ would be higher than $P_1$. Thus,statement $C$ is incorrect.$4$. Sublimation occurs at pressures below the triple point $(O)$. Therefore,the sublimation temperature is always less than the triple point temperature. Thus,statement $D$ is correct.$5$. The incorrect statement is $C$.

List-$I$	List-$II$
$(A)$ Viscosity	$(I)$ Critical temperature
$(B)$ Ideal gas behaviour	$(II)$ Isobars
$(C)$ Liquefaction of gases	$(III)$ Compressibility factor
$(D)$ Charles' law	$(IV)$ $kg \ s^{-2}$
	$(V)$ $kg \ m^{-1} \ s^{-1}$

Select the incorrect statement using the phase diagram of a substance.

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