Show that $A \cap B = A \cap C$ does not necessarily imply $B = C$.
(N/A) Let $A = \{0, 1\}, B = \{0, 2, 3\},$ and $C = \{0, 4, 5\}$.
Accordingly,$A \cap B = \{0\}$ and $A \cap C = \{0\}$.
Here,$A \cap B = A \cap C = \{0\}$.
However,$B \neq C$ because $2 \in B$ and $2 \notin C$.
Accordingly,$A \cap B = \{0\}$ and $A \cap C = \{0\}$.
Here,$A \cap B = A \cap C = \{0\}$.
However,$B \neq C$ because $2 \in B$ and $2 \notin C$.
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