Sodium and copper have work functions 2.3 eV | vedclass

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(B) The work function $\Phi$ is related to the threshold wavelength $\lambda_0$ by the equation: $\Phi = \frac{hc}{\lambda_0}$.This implies that $\lam

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$2: 1$

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(B) The work function $\Phi$ is related to the threshold wavelength $\lambda_0$ by the equation: $\Phi = \frac{hc}{\lambda_0}$.This implies that $\lambda_0 = \frac{hc}{\Phi}$.Let $\Phi_{Na} = 2.3 \ eV$ and $\Phi_{Cu} = 4.5 \ eV$.The ratio of the threshold wavelengths is given by: $\frac{\lambda_{Na}}{\lambda_{Cu}} = \frac{hc / \Phi_{Na}}{hc / \Phi_{Cu}} = \frac{\Phi_{Cu}}{\Phi_{Na}}$.Substituting the given values: $\frac{\lambda_{Na}}{\lambda_{Cu}} = \frac{4.5}{2.3} \approx 1.956$.Rounding this value to the nearest option,we get $2: 1$.

Sodium and copper have work functions $2.3 \ eV$ and $4.5 \ eV$ respectively. The ratio of the threshold wavelength of sodium to that of copper is nearest to:

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