Solve the equation sqrt{3} x^{2}-sqrt{2} x+3 | vedclass

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(A) The given quadratic equation is $\sqrt{3} x^{2}-\sqrt{2} x+3 \sqrt{3}=0$.Comparing this with $a x^{2}+b x+c=0$,we get $a=\sqrt{3}, b=-\sqrt{2}, c=

Vedclass · Accepted Answer

$\frac{\sqrt{2} \pm \sqrt{34} i}{2 \sqrt{3}}$

Vedclass · Answer

(A) The given quadratic equation is $\sqrt{3} x^{2}-\sqrt{2} x+3 \sqrt{3}=0$.Comparing this with $a x^{2}+b x+c=0$,we get $a=\sqrt{3}, b=-\sqrt{2}, c=3 \sqrt{3}$.The discriminant $D$ is given by $D = b^{2}-4ac$.$D = (-\sqrt{2})^{2} - 4(\sqrt{3})(3 \sqrt{3}) = 2 - 4(3)(3) = 2 - 36 = -34$.The roots are given by $x = \frac{-b \pm \sqrt{D}}{2a}$.$x = \frac{-(-\sqrt{2}) \pm \sqrt{-34}}{2 \sqrt{3}} = \frac{\sqrt{2} \pm \sqrt{34} i}{2 \sqrt{3}}$ (since $\sqrt{-1} = i$).

Solve the equation $\sqrt{3} x^{2}-\sqrt{2} x+3 \sqrt{3}=0$.

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