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Question

(B) For the quadratic equation $ax^{2}+bx+c=0$,the quadratic formula is $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$.Comparing $x^{2}+5x+3=0$ with the sta

Vedclass · Accepted Answer

$\frac{-5+\sqrt{13}}{2}, \frac{-5-\sqrt{13}}{2}$

Vedclass · Answer

(B) For the quadratic equation $ax^{2}+bx+c=0$,the quadratic formula is $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$.Comparing $x^{2}+5x+3=0$ with the standard form,we get $a=1, b=5, c=3$.The discriminant $D = b^{2}-4ac = (5)^{2} - 4(1)(3) = 25 - 12 = 13$.Since $D > 0$,real solutions exist.Substituting the values into the formula: $x = \frac{-5 \pm \sqrt{13}}{2(1)}$.Thus,the solutions are $x = \frac{-5+\sqrt{13}}{2}$ and $x = \frac{-5-\sqrt{13}}{2}$.

Solve the following quadratic equation using the quadratic formula,if the equation has a solution in $R$: $x^{2}+5x+3=0$.

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