Solve the following pair of linear equations | vedclass

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(B) The given equations are:$3x + y - 7 = 0$  --- $(i)$$2x + 3y - 14 = 0$ --- $(ii)$Using the cross-multiplication method,the formula is:$\frac{x}{b_1

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$(1, 4)$

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(B) The given equations are:$3x + y - 7 = 0$  --- $(i)$$2x + 3y - 14 = 0$ --- $(ii)$Using the cross-multiplication method,the formula is:$\frac{x}{b_1c_2 - b_2c_1} = \frac{y}{c_1a_2 - c_2a_1} = \frac{1}{a_1b_2 - a_2b_1}$Here,$a_1 = 3, b_1 = 1, c_1 = -7$ and $a_2 = 2, b_2 = 3, c_2 = -14$.Substituting the values:$\frac{x}{(1)(-14) - (3)(-7)} = \frac{y}{(-7)(2) - (-14)(3)} = \frac{1}{(3)(3) - (2)(1)}$$\frac{x}{-14 + 21} = \frac{y}{-14 + 42} = \frac{1}{9 - 2}$$\frac{x}{7} = \frac{y}{28} = \frac{1}{7}$For $x$: $\frac{x}{7} = \frac{1}{7} \implies x = 1$For $y$: $\frac{y}{28} = \frac{1}{7} \implies y = 4$Thus,the solution is $(1, 4)$.

Solve the following pair of linear equations by the cross-multiplication method:
$3x + y = 7$
$2x + 3y = 14$

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Solve the following pair of linear equations by the cross-multiplication method:$3x + y = 7$$2x + 3y = 14$