Solve the following system of inequalities graphically: $2x + y \geq 6, 3x + 4y \leq 12$

(N/A) $2x + y \geq 6$ ..... $(1)$
$3x + 4y \leq 12$ ..... $(2)$
The graph of the lines $2x + y = 6$ and $3x + 4y = 12$ are drawn in the figure. Inequality $(1)$ represents the region above the line $2x + y = 6$ (including the line $2x + y = 6$),and inequality $(2)$ represents the region below the line $3x + 4y = 12$ (including the line $3x + 4y = 12$).
Hence,the solution of the given system of linear inequalities is represented by the common shaded region including the points on the respective lines as shown in the figure.