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(B) To determine the nature of the region,we analyze the given inequalities:$1$. $x \geq 6$: This represents the region to the right of the vertical l

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unbounded

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(B) To determine the nature of the region,we analyze the given inequalities:$1$. $x \geq 6$: This represents the region to the right of the vertical line $x = 6$.$2$. $y \geq 3$: This represents the region above the horizontal line $y = 3$.$3$. $2x + y \geq 10$: This represents the region on or above the line $2x + y = 10$.$4$. $x \geq 0, y \geq 0$: These represent the first quadrant.By plotting these lines,we observe that the intersection of these regions starts from the point $(6, 3)$ and extends infinitely in the positive $x$ and $y$ directions.Since the region does not have a finite area and extends infinitely,it is an unbounded region.Therefore,the correct option is $B$.

The region represented by the inequalities $x \geq 6, y \geq 3, 2x + y \geq 10, x \geq 0, y \geq 0$ is

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The region represented by the inequalities $x \geq 6, y \geq 3, 2x + y \geq 10, x \geq 0, y \geq 0$ is

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$x \geq 2$ ..... $(2)$
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$x+y \geq 5$ ..... $(1)$
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