The shaded region in the figure is the soluti | vedclass

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Question

(A) $1$. The line passes through the points $(0, 5)$ and $(4, 0)$. The equation of this line is given by the intercept form: $\frac{x}{4} + \frac{y}{5

Vedclass · Accepted Answer

$5x + 4y \geq 20, x \leq 6, y \leq 3, x \geq 0, y \geq 0$

Vedclass · Answer

(A) $1$. The line passes through the points $(0, 5)$ and $(4, 0)$. The equation of this line is given by the intercept form: $\frac{x}{4} + \frac{y}{5} = 1$,which simplifies to $5x + 4y = 20$. Since the shaded region is above the line,the inequality is $5x + 4y \geq 20$.$2$. The region is bounded by the vertical line $x = 6$ on the right,and since the shaded area is to the left of this line,we have $x \leq 6$.$3$. The region is bounded by the horizontal line $y = 3$ on the top,and since the shaded area is below this line,we have $y \leq 3$.$4$. The region is in the first quadrant,so $x \geq 0$ and $y \geq 0$.$5$. Combining all these,the system of inequations is $5x + 4y \geq 20, x \leq 6, y \leq 3, x \geq 0, y \geq 0$.

The shaded region in the figure is the solution set of the inequations:

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